Mysql 实现 向上递归查找父节点并返回树结构

SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;
 
-- ----------------------------
-- Table structure for Menu
-- ----------------------------
DROP TABLE IF EXISTS `Menu`;
CREATE TABLE `Menu` (
  `menu_id` varchar(255) COLLATE utf8mb4_bin NOT NULL DEFAULT '0',
  `sup_menu` varchar(255) COLLATE utf8mb4_bin DEFAULT NULL,
  `auth_id` varchar(255) COLLATE utf8mb4_bin DEFAULT NULL,
  PRIMARY KEY (`menu_id`) USING BTREE
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_bin;
 
-- ----------------------------
-- Records of Menu
-- ----------------------------
BEGIN;
INSERT INTO `Menu` VALUES ('1', NULL, '1');
INSERT INTO `Menu` VALUES ('11', NULL, '11');
INSERT INTO `Menu` VALUES ('12', '11', '12');
INSERT INTO `Menu` VALUES ('13', '11', '13');
INSERT INTO `Menu` VALUES ('14', '12', '14');
INSERT INTO `Menu` VALUES ('15', '12', '15');
INSERT INTO `Menu` VALUES ('16', '13', '16');
INSERT INTO `Menu` VALUES ('17', '13', '17');
INSERT INTO `Menu` VALUES ('2', '1', '2');
INSERT INTO `Menu` VALUES ('22', '21', '26');
INSERT INTO `Menu` VALUES ('25', '22', '25');
INSERT INTO `Menu` VALUES ('3', '1', '3');
INSERT INTO `Menu` VALUES ('4', '2', '4');
INSERT INTO `Menu` VALUES ('5', '2', '5');
INSERT INTO `Menu` VALUES ('6', '3', '6');
INSERT INTO `Menu` VALUES ('7', '3', '7');
COMMIT;
 
SET FOREIGN_KEY_CHECKS = 1;

方法一：纯存储过程实现

-- 纯存储过程实现
DELIMITER //
-- 如果只有叶子，剔除掉; 如果只有根，只显示一个秃顶的根 ；如果既有叶子又有根则显示
DROP PROCEDURE if EXISTS  query_menu_by_authid;
CREATE PROCEDURE query_menu_by_authid(IN roleIds varchar(1000))

BEGIN
-- 用于判断是否结束循环
declare done int default 0;
-- 用于存储结果集
declare menuid bigint;
declare temp_menu_ids VARCHAR(3000);
declare temp_sup_menus VARCHAR(3000);
declare return_menu_ids VARCHAR(3000);

-- 定义游标
declare idCur cursor for select menu_id from Menu where  FIND_IN_SET(auth_id,roleIds) ;
-- 定义 设置循环结束标识done值怎么改变 的逻辑
declare continue handler for not FOUND set done = 1;


open idCur ;
FETCH idCur INTO menuid;
-- 临时变量存储menu_id集合
SET temp_menu_ids = '';
-- 返回存储menu_id集合
SET return_menu_ids = '';

WHILE done<> 1 DO
--  只查找 单个 auth_id  相关的menu_id
-- 通过authid, 查找出menu_id, sup_menu is null

SELECT
GROUP_CONCAT(T2._menu_id) as t_menu_id,
GROUP_CONCAT(T2._sup_menu) as t_sup_menu
into temp_menu_ids,temp_sup_menus
FROM
     (
       SELECT
       -- 保存当前节点。（从叶节点往根节点找，@r 保存当前到哪个位置了）。@r 初始为要找的节点。
       -- _menu_id 当前节点
       DISTINCT @r as _menu_id,
             (
           SELECT
             CASE
                        WHEN sup_menu IS NULL THEN @r:= 'NULL'
                        ELSE @r:= sup_menu
             END
             FROM Menu
             WHERE  _menu_id = Menu.menu_id
             ) AS _sup_menu,
       -- 保存当前的Level
       @l := @l + 1 AS level
       FROM
       ( SELECT @r := menuid, @l := 0
       ) vars, Menu AS temp
        -- 如果该节点没有父节点，则会被置为0
        WHERE  @r <> 0
        ORDER BY @l DESC
       ) T2
      INNER JOIN Menu T1
    ON T2._menu_id = T1.menu_id
 ORDER BY T2.level DESC ;

 -- 满足必须要有根节点NULL字符，则表明有根，否则不拼接给返回值
 IF FIND_IN_SET('NULL',temp_sup_menus) > 0  THEN
 SET return_menu_ids = CONCAT(temp_menu_ids,',',return_menu_ids);
 END IF;

FETCH idCur INTO menuid;
END WHILE;
CLOSE  idCur;

-- 返回指定menu_id 的数据集合
select Menu.menu_id,Menu.sup_menu,Menu.auth_id
FROM Menu
WHERE FIND_IN_SET(menu_id,return_menu_ids)
ORDER BY Menu.menu_id*1 ASC ;

END;
//
DELIMITER;

CALL  query_menu_by_authid('5,15,25,26');
CALL  query_menu_by_authid('5,17');
CALL  query_menu_by_authid('5,11');

方法二：函数+存储过程实现

-- 函数+存储过程实现
-- 根据叶子节点查找所有父节点及其本身节点。如果只有叶子，剔除掉; 如果只有根，只显示一个秃顶的根 ；如果既有叶子又有根则显示.
DROP FUNCTION  IF EXISTS `getParentList`;
CREATE FUNCTION `getParentList`(in_menu_id varchar(255))
RETURNS varchar(3000)
BEGIN
    DECLARE sTemp VARCHAR(3000);
    DECLARE sTempPar VARCHAR(3000);
    SET sTemp = '';
    SET sTempPar = in_menu_id;

    -- 循环递归
    WHILE sTempPar is not null DO
        -- 判断是否是第一个，不加的话第一个会为空
        IF sTemp != '' THEN
            SET sTemp = concat(sTemp,',',sTempPar);
        ELSE
            SET sTemp = sTempPar;
        END IF;
        SET sTemp = concat(sTemp,',',sTempPar);
        SELECT group_concat(sup_menu)
                INTO sTempPar
                FROM Menu
                where sup_menu<>menu_id
                and FIND_IN_SET(menu_id,sTempPar) > 0;
    END WHILE;
    RETURN sTemp;
END;


DELIMITER //
-- 如果只有叶子，剔除掉; 如果只有根，只显示一个秃顶的根 ；如果既有叶子又有根则显示
DROP PROCEDURE if EXISTS  select_menu_by_authids ;
CREATE PROCEDURE select_menu_by_authids(IN roleIds varchar(3000))

BEGIN
-- 用于判断是否结束循环
declare done int default 0;
-- 用于存储结果集
declare menuid varchar(255);
declare set_menu_ids VARCHAR(3000);
--  检查是否单叶子节点 单叶子节点 sup_menu is not null
-- sup_menu 是否为null
declare _sup_menu int default -1;

-- 定义游标
declare idCur cursor for select menu_id from Menu where  FIND_IN_SET(auth_id,roleIds) ;
-- 定义 设置循环结束标识done值怎么改变 的逻辑
declare continue handler for not FOUND set done = 1;

OPEN idCur ;
FETCH idCur INTO menuid;
-- 临时变量存储menu_id集合
SET set_menu_ids = '';

WHILE done<> 1 DO
SELECT  sup_menu
INTO _sup_menu
FROM Menu
WHERE FIND_IN_SET(menu_id,getParentList(menuid))
ORDER BY sup_menu ASC
LIMIT 1;

-- 查找指定角色对应的menu_id ，sup_menu is null 则说明有根，则进行拼接
IF _sup_menu is NULL THEN
SELECT  CONCAT(set_menu_ids, GROUP_CONCAT(menu_id),',') INTO set_menu_ids
FROM Menu
where FIND_IN_SET(menu_id,getParentList(menuid)) ;
END IF;

FETCH idCur INTO menuid;
END WHILE;
CLOSE  idCur;

-- 返回指定menu_id 的数据集合
SELECT Menu.menu_id,Menu.sup_menu,Menu.auth_id
FROM Menu
WHERE FIND_IN_SET(menu_id,set_menu_ids)
ORDER BY Menu.menu_id*1 ASC  ;

END ;
//
DELIMITER ;

CALL  select_menu_by_authids('5,15,25,26');
CALL  select_menu_by_authids('5,17');
CALL  select_menu_by_authids('5,11');

方法三：纯函数实现

-- 根据叶子节点查找所有父节点及其本身节点。如果只有叶子，剔除掉; 如果只有根，只显示一个秃顶的根 ；如果既有叶子又有根则显示.
DROP FUNCTION  IF EXISTS `getParentLists`;
-- 参数1角色id 字符串逗号隔开； 参数2 角色id 个数
CREATE FUNCTION `getParentLists`(in_roleIds varchar(1000),count_roleIds INT)
RETURNS VARCHAR(3000)
BEGIN
    -- 临时存放通过单个角色查找的单个menu_id
        DECLARE sMenu_id_by_roleId VARCHAR(1000);
    -- 临时存放通过单个角色查找的多个menu_id
    DECLARE sMenu_ids_by_roleId VARCHAR(1000);
        -- 临时存放通过多个角色查找的多个menu_id
    DECLARE sMenu_ids_by_roleIds VARCHAR(1000);
        -- 函数返回的menu_id 集合
        DECLARE sReturn_menu_ids VARCHAR(3000);
        -- 当前角色
    DECLARE current_roleId_rows INT DEFAULT 0;

        SET sMenu_id_by_roleId = '';
    SET sMenu_ids_by_roleIds = '';
        SET sReturn_menu_ids = '';

         -- 循环多角色
        WHILE current_roleId_rows < count_roleIds DO

                -- 依次按角色取1条menu_id
                SELECT menu_id
                INTO sMenu_id_by_roleId
                FROM Menu
                WHERE FIND_IN_SET(auth_id, in_roleIds)
                ORDER BY menu_id DESC
                LIMIT current_roleId_rows, 1 ;

                SET sMenu_ids_by_roleId = sMenu_id_by_roleId;
        WHILE sMenu_ids_by_roleId IS NOT NULL DO

                        -- 判断是否是第一个，不加的话第一个会为空
                        IF sMenu_ids_by_roleIds != ''  THEN
                                SET sMenu_ids_by_roleIds = CONCAT(sMenu_ids_by_roleIds,',',sMenu_ids_by_roleId);
                        ELSE
                                SET sMenu_ids_by_roleIds = sMenu_ids_by_roleId;
                        END IF;

                        -- 通过角色id 拼接 所有的父节点，重点拼接根节点，根节点置为字符NULL，用于后面判断是否有根
                        SELECT
                        GROUP_CONCAT(
                        CASE
                        WHEN sup_menu IS NULL THEN  'NULL'
                        ELSE sup_menu
                        END
                        )
                        INTO sMenu_ids_by_roleId
                        FROM Menu
                        WHERE FIND_IN_SET(menu_id,sMenu_ids_by_roleId) > 0;

       END WHILE;
             SET current_roleId_rows=current_roleId_rows+1;

             -- 满足必须要有根节点NULL字符，则表明有根，否则不拼接给返回值
             IF  FIND_IN_SET('NULL',sMenu_ids_by_roleIds) > 0 THEN
                         SET sReturn_menu_ids = CONCAT(sReturn_menu_ids,',',sMenu_ids_by_roleIds);
             END IF;

             -- 清空通过单个角色查到的多个menu_id, 避免重复拼接
             SET sMenu_ids_by_roleIds = '';
   END WHILE;

   RETURN sReturn_menu_ids;
END;

SELECT Menu.menu_id,Menu.sup_menu,Menu.auth_id
FROM Menu
WHERE FIND_IN_SET(menu_id, getParentLists('15,25,5,26',4))
ORDER BY Menu.menu_id+0 ASC;

SELECT Menu.menu_id,Menu.sup_menu,Menu.auth_id
FROM Menu
WHERE FIND_IN_SET(menu_id, getParentLists('17,5',2))
ORDER BY Menu.menu_id*1 ASC;

SELECT Menu.menu_id,Menu.sup_menu,Menu.auth_id
FROM Menu
WHERE FIND_IN_SET(menu_id, getParentLists('11,5',2))
ORDER BY Menu.menu_id*2 ASC;

转载至：https://www.cnblogs.com/zjp8023/p/16684032.html